x = 1 while x < 10: if x%2 == 0: print(str(x) + " is even") else: print(str(x) + " is odd") elif:

Question

Brother and sister help this programming error

Answer 1

Between the error was u didn't increment the loop so it was continuously showing for the initial value and elif won't come after else

https://code.sololearn.com/crerg4Cgy9R0/?ref=app

Answer 2

Thanks 👍 bro

Answer 3

https://code.sololearn.com/cEDnhy3g12cn/?ref=app

Answer 4

x = 1
while x < 10:
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")

x += 1

x%2 == 0: explain this line please

Answer 5

x = int(input())
while x < 10:
if x%2 == 0:
print(str(x) + " is even")
break
else:
print(str(x) + " is odd")
break
See above code and don't use last line.

Answer 6

Thanks 👍 bro