What is the error in my code???

Question

msg1=input()
ms1=msg1.split()
dict1={'0':"zero",'1':"one",'3':"two",'3':"three",'4':"four",5:"five",'6':"six",'7':"seven",'8':"eight",
'9':"nine"}
msg2=[]

for i in ms1:
if i.isdigit():

msg2.append(dict1[i])

else:
msg2.append(i)
ms3=' '.join(msg2)
print(ms3)

Answer 1

msg1=input()
ms1=msg1.split()
dict1={'1':"one",'2':"two",'3':"three",'4':"four",'5':"five",'6':"six",'7':"seven",'8':"eight",
'9':"nine",'10':"ten"}
msg2=[]

for i in ms1:
if i.isdigit():

msg2.append(dict1[i])

else:
msg2.append(i)
ms3=' '.join(msg2)
print(ms3)

# (Jayndra Todawat no changes in code, only added "10":"ten" to dict1 and little modification with dict1 and its working like charm)

Answer 2

~ swim ~
RKK
Thnx for suggestions.

Answer 3

~ swim ~ Then plz help me to deal with it.

Answer 4

RKK
~ swim ~
But test case 6 is failing.
Whats the problem then???

Answer 5

Jayndra Todawat

dict1={'0':"zero",'1':"one",'3':"two",'3':"three",'4':"four",5:"five",'6':"six",'7':"seven",'8':"eight"...

check your key value nicely..

you have '3':'two' and also 5 is missing single quotes and also add '10':"ten"

Answer 6

~ swim ~ you're right, the code would break/fail for input like "abcd10efg" and I agree with you too that char scanning would be a good solution.