Please tell me what's wrong in this code.

Question

when I run this code the analyser says, syntax error in line9

side1 = int(input())
side2 = int(input())
side3 = int(input())
side3>side1
side3>side2
side1**2=x
side2**2=y
side3**2=z
if x+y=z:
print("Right-angled")
else:
print("Not right-angled")

Answer 1

Samudra Saikia , yes sure - your code is for practice, but what is the purpose of this code? I assume it is to check if a triangle with 3 given sides is a right-angled triangle. So this information should be given when posting the question.
if so the code for it could be done like:

# input 3 values separated by space
# input of the 3 values will be splitted, converted to int and stored in a list inp
inp = [int(i) for i in input('values for a, b, c: ').split()]
if inp[0]**2 + inp[1]**2 == inp[2]**2:
print(True)
else:
print(False)

#or in a more compact form use this:
inp = [int(i) for i in input('values for a, b, c: ').split()]
print(True) if inp[0]**2 + inp[1]**2 == inp[2]**2 else False

Answer 2

Samudra Saikia , can you please tell us, what you try to achieve with this code. Thanks!

Answer 3

Oh try if x+y==z:
As far as i know = is the assignment operator and == is for comparison:)
If this still doesn't work you could try to store x+y in another variable and compare that with z :)

Answer 4

Single '=' is an assignment operator, it cannot be used to compare two operator, Hence you should use '==' operator.

Answer 5

Maybe you're missing a space or tab?

Answer 6

I don't think so, what should I try to fix it

Answer 7

I can tell that there's no problem in those things, I tried it all. Its a problem with the if statement

Answer 8

its the same fixing problem here too
color = input()
if color=red:
print('1')
elif color=green:
print('2')
elif color=black:
print('3')
else:
print()
when I run it the analyser says invalid syntax line2

Answer 9

and in this one too
number = input()
if number%2=0:
print(number**2)
elif number%3=0
print(number**3)
else number=0
print("0")
invalid syntax line2
can anyone tell me what's wrong here

Answer 10

anyone please

Answer 11

https://code.sololearn.com/coKCfNdBXi31/?ref=app

Works just fine here.

Answer 12

Christian Hauck is right, same problem in the other two codes as same single '=' in them too.

Answer 13

that code was to practice

Answer 14

Christian Hauck thanks

Answer 15

If x+y=z has no items since they don't exist as variables.

Answer 16

color = input()
if color=='red':
print('1')
elif color=='green':
print('2')
elif color=='black':
print('3')
else:
print('4')

Answer 17

Hello