tuples = [(), ('ram','15','8'), (), ('laxman', 'sita'), ('krishna', '45'), ('',''),()] remove empty tuple without filer()

Question

Use if

Answer 1

Jayakrishna🇮🇳 it is a list of tuples

Answer 2

Oma Falk sure but it wasn't there in the question so I did not include any other case. Jayakrishna🇮🇳 yes probably you misinterpreted the question at first.

Answer 3

Avinesh
if not tuple
should do it too.

Answer 4

Oh. Yes. Thanks for clarification..
Oma Falk then it works as @Avinesh said..

Answer 5

Jayakrishna🇮🇳 it almost works everything as Avinesh says😉

Answer 6

U can use a list comprehension:
tuples = [t for t in tuples if t]

https://code.sololearn.com/czCzbLpH9uuj/?ref=app

Answer 7

tuples = [(), ('ram','15','8'), (), ('laxman', 'sita'), ('krishna', '45'), ('',''),()]
for x in tuples:
if len(x) == 0:
tuples.remove(x)

Answer 8

This should work I guess.

for tuple in tuples:
if tuple == ():
tuples.remove(tuple)

Answer 9

Tuple are immutable.
That is list. But tagged tuple.
Is it list or tuple?

Answer 10

Avinesh yes. I edited, I seen only () so assumed as tuple as it was named also.. Tagged tuple too..

Answer 11

I just wondered Mounika if the ('','') is also for you an empty tuple. If yes then the above Avinesh code can be extended as follows:

for tuple in tuples:
if(tuple == ()):
tuples.remove(tuple)
for tuple in tuples:
flag = False
for item in tuple:
if(item != ''):
flag = False
break
else:
flag = True
if(flag):
tuples.remove(tuple)
print(tuples)

Answer 12

Avinesh Because the list size changes the loop would only iterate through every second item in the list.

But this should work:
for i in range(len(tuples) - 1, -1, -1):
if not tuples[i]:
tuples.pop(i)