Can anyone explain every code repeated to 'started' variable in the following code?

Question

#include <stdio.h>
int main()
{
float latitude;
float longitude;
char info[80];
int started = 0;
puts("data=[");
while (scanf("%f,%f,%79[^\n]",&latitude , &longitude,info ) == 3) {
if (started)
printf(",\n");
else
started =1 ;
printf("{latitude: %f, longitude: %f, info: '%s'}", latitude, longitude, info);
}
puts("\n]");
return 0;
}

Answer 1

Oh I see ...

Well, before the loop begin you assigned 0 for variable <started>. Being zero, this means <started> is evaluable as false e.g. in your `if` branch inside loop body.

When the loop starts, <started> value was 0, so `else` block is executed, which sets <started> to 1. On successive loop iterations, <started> value will be 1, and thus the `if` block will be executed.

The `else` block is only executed once, in the first loop iteration ...

(EDITED)

Answer 2

I didn't understand the question. Can you elaborate more clearly please?

Answer 3

I mean "if(started) and else started = 1" in this code the first is true and should break but why the else statement still be run?