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Hay forma de hacer esto? Debo hacerlo para la universidad, ayuda por favor :(

https://www.sololearn.com/discuss/2468891/?ref=app

31st Aug 2020, 12:28 PM
Miguel Ángel Puerta Reyes
Miguel Ángel Puerta Reyes - avatar
4 odpowiedzi
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Debe probar y publicar su prueba. Puede utilizar el método de subcadena s.substring (i, i + 2); para extraer 2 caracteres y comparar. Puede usar un bucle y hacer como string.charAt (i) == string.charAt (i + 1) && (string.charAt (i)! = 'R' || string.charAt (i)! = 'L' )) en bucle .. Espero que ayude .. (translated this) You need to try and please post your try.. You can use substring method s.substring(i,i+2); to extract 2 charecters and compare. You can use a loop and do like string.charAt(i) == string.charAt(i+1) && (string.charAt(i)! ='R' || string.charAt(i)!='L')) in loop.. Hope it helps..
31st Aug 2020, 3:48 PM
Jayakrishna 🇮🇳
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Jayakrishna🇮🇳 Could you make the code for me please? 🙏 is for tomorrow😞
1st Sep 2020, 12:11 AM
Miguel Ángel Puerta Reyes
Miguel Ángel Puerta Reyes - avatar
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You are saying to me to make a crime almost.. You should atleast give a try.. I almost given main condition for your problem.. You just need to take input and add a loop..
1st Sep 2020, 3:42 PM
Jayakrishna 🇮🇳
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Miguel Ángel Puerta Reyes Only this time, please never ask only code to any one , pls try yourself first.. import java.util.Scanner; public class Program { public static void main(String[] args) { Scanner in = new Scanner(System.in); String str=in.next(); boolean s=false; for(int i =0; i<str.length()-1;i++){ if(str.charAt(i) == str.charAt(i+1)) if(str.charAt(i)!='R' && str.charAt(i)!='L')) { s = true; break; } } System.out.println(s); // by using substring method /* if(str.contains("RR") || str.contains("LL")) System.out.println(false); else for(int i =0; i<str.length()-1;i++){ if(str.charAt(i) == str.charAt(i+1)) { s = true; break; } } System.out.print(s); */ } }
1st Sep 2020, 4:06 PM
Jayakrishna 🇮🇳