How it's possible to output 256? Anyone can tell me.

Question

int n=2, m=3;
while(m--)
n*=n;
printf("%d",n);

Answer 1

M=3....n=2*2=4
M=2 ...n= 4*4=16
M=1...n= 16*16=256
Stop

Answer 2

m-- means the present value of m will be considered and then it will get decremented!

First loop:
Checking conditon:
m = 3 ✅
Executing the block:
n = n*n => 2*2 => 4

Second loop:
Checking conditon:
m = 2 ✅
Executing the block:
n = n*n => 4*4 => 16

Third loop:
Checking conditon:
m = 1 ✅
Executing the block:
n = n*n => 16*16 => 256

First loop:
Checking conditon:
m = 0 ❌ (0 and false are both falsy)
Loop breaks!

Final value of n = 256

Answer 3

Loop stops when value is decreased to 0 and 0 is evaluated as false which stops further execution of while loop

Answer 4

First read about loops and conditions you will understood much better . Always do dry run in rough copy and write all Values how it changing.

Output will be 256 because int n =2 ,m=3 in while loop you wrote m
While(m--) when first time loop will run it will be while(3--) here value will be decrease after that n*=n means n=2*2 (here n=2)
Now n=4 then loop will run again m will be 2 now then n*=n ,n=4*4, n=16 then again loop will run and now value of m will be 1 so again
n*=n , n=16*16=256 then m-- here m will be 0 so final answer 256 will print on screen

You asked same question before in cpp but their m was m =2 but u asking how answer was 256
.
https://www.sololearn.com/Discuss/2458725/?ref=app

Answer 5

While m--
means
as long as m >0

Answer 6

Oma Falk here mention not any condition that m value 3 is decreasing upto 1, so how l'm decide that?