I created this code to find the middle element's index of any list .

Question

If the number of element's is an even number it will show index number of two middle elements and if it is an odd number it will show the middle element's index number
Is this code correct ?
Is there any other easy method ?
Help me ☺️

https://code.sololearn.com/cg1b850Jg0CL/?ref=app

Answer 1

Sure! It is correct and clear...
Just replace all slashes with double slashes, so the result will be integers

Answer 2

def mid(arr) :
if len(arr) <3:
return arr
return mid(arr[1:-1])
print(mid([1,3,5,7,78,5,8,6]))

find middle wirhout index.

Answer 3

Never use built-in names as variable names. list is the name of the base class of all list intances and you should never use that name as identifier.

When the list is empty wrong indeces are shown but the code works perfectly otherwise. There are shorter and less redundant ways to write that code, but yours isn't bad.
Also follow Bilbo Baggins' advice.

Answer 4

Thanks to all

Answer 5

You can take advantage of the fact that integer division // returns the same value for two consecutive numbers.
To simplify your code, you can check this example.

I am not sure why you need the actual indices. If you want the middle elements, you can also directly slice a list using similar formula.

https://code.sololearn.com/ciO4voCEXpOZ/?ref=app

Answer 6

The answer is easier than that:

print(len(items)//2)

Hope i helped

Answer 7

items = [2, 4,6,8, 10, 12, 14]

num = len(items) // 2
print(num)

Answer 8

How many elements will this slice return if the "names" list contains 5 items?

names[1:-1]

Answer 9

list="names"
print(list[1:-1])

answer: ame

Answer 10

list="names"
print(list[1:-1])

answer: 3

Answer 11

3

Answer 12

How many elements will this slice return if the "names"list contains 5items?

names[1:-1]

Answer 13

How many elements will this slice return if the "names" list contains 5 items?

names[1:-1]

Answer 14

answer