Why the code doesn't show odd letters in the word? Also, The letters should be sorted in ascending order

Question

text = "apple"
t = sorted(text)
for i in range(len(text)) :
if i % 2 == 0:
print(t[I])

Answer 1

Hi, can you please tag Python as the relevant language up there? ☝

And tell me how output should be by that input, coz I'm not getting what you mean by "odd letters"

Answer 2

Thank you very much 😇

Answer 3

Sort alphabetically

Answer 4

Try now you did one mistake in print statement you wrote capital I instead of small i .

text = "apple"
t = sorted(text)
for i in range(len(text)) :
if i % 2 == 1:
print(t[i])

Answer 5

text = "apple"
t = sorted(text)
for i in range(len(text)) :
if i % 2 == 1:
print(t[i],end="") #end ="" for printing in same line...

Edit : Марина for odd only.. Oh. Edited.
i%2=0, =>I is even, i%2=1 odd.

Answer 6

Yes. Sorted works..check

text = "apple"
t = sorted(text)
print(t) #output : a, e, l, p, p