Can some one expain me ?

Question

Int main()
Int a=4,b=3;
a=a^b;
b=a^b;
a=a^b;
Printf("after xoR ,a=%d and b=%d",a,b);

Answer 1

Sonam aafre

This is called Bitwise Exclusive OR ^
It works like this.

1st operand 2nd operand resultant bit
0 0 0
0 1 1
1 0 1
1 1 0

a = 4 = 0 0 0 0 0 1 0 0 (in binary)
b = 3 = 0 0 0 0 0 0 1 1

Now compare the corresponding bit of first operand with second operand.
a = a^b = ( 0 0 0 0 0 1 0 0 ) ^ (0 0 0 0 0 0 1 1) = 0 0 0 0 0 1 1 1

b = a^b = (0 0 0 0 0 1 1 1) ^ (0 0 0 0 0 0 1 1) = 0 0 0 0 0 1 0 0 = 4

a = a^b = (0 0 0 0 0 1 1 1) ^ (0 0 0 0 0 1 0 0 ) = 0 0 0 0 0 0 1 1 = 3

That's why result is a = 3 and b = 4.
https://www.sololearn.com/learn/4074/?ref=app

Answer 2

See this page
https://en.m.wikipedia.org/wiki/Bitwise_operations_in_C

Answer 3

Thank u so much ☺️☺️

Answer 4

But answer to a=3 and b=4 aarha he