Any efficient solution for this problem ?

Question

The day corresponding to the first day of a month and a date is given as input. The program must print the day of the date .
I/p : MON
10
o/p : WED
Exp: If the first day of the month is Monday and the day on 10th of that month is on Wednesday.

Answer 1

Mndm , here is a short version of rotating a list. "d" is the number to rotate the items from the iterable "arr". pos number is shift left, neg number is shift right.

# rotate list
def rotate(arr, d):
return arr[d:] + arr[:d]

Answer 2

Here is my version: (it uses a list that will be shifted once, so it avoids iterating through date)

day = input()
date = int(input())
days = [ 'MON', 'TUE', 'WED', 'THU', 'FRI', 'SAT', 'SUN']

shift = days.index(day)
arr = days[shift:] + days[:shift]
print(arr[(date % 7) -1])

Answer 3

Please show us your attempt first, before we can help you. put your try in playground and link it here. Thanks!

Answer 4

I give you hints
1. Make a tuple of 7 elements having Days of Week in sequence (important)
2. Find the First day in tuple and store it's index in a variable , suppose x....
3. Then make a loop that iterate over that tuple starting from index (x) and stop when we reaches the date...

Answer 5

Do you have any idea written as some lines of code?

Answer 6

Lothar Avalon

https://code.sololearn.com/cY69UFgs3XMX/?ref=app

I have attached the code. But I can't get the output.
Here I iterated through the list 'days'. Any simple code for list rotation ?? Thank you !!

Answer 7

day = input().strip()
date = int(input())
days = [ 'MON', 'TUE', 'WED', 'THU', 'FRI', 'SAT', 'SUN']
x = days.index(day)
y = x
for i in range(date):
y+=1
if days[y]=='SUN':
y=0
print(days[y-1])

Answer 8

This could help:
https://code.sololearn.com/c9UstEsAJo6v/?ref=app