Please can someone help with the code to BOOK TITLES and PHONE NUMBER VALIDATOR in python.

Answer 1

https://code.sololearn.com/c5LfMwEmIx2v/?ref=app

for book titles you can refer to the code above and if you have any problems just ask me

Phone validator:
first you need to define a function to count the no. of characters in the input and then apply if condition.

txt=input()
def count(text):
count=0
for c in text:
count+=1
return count

if txt.startswith("1") and count(txt)==8:
print("valid")
elif txt.startswith("8") and count(txt)==8:
print("valid")
elif txt.startswith("9") and count(txt)==8:
print("valid")
else:
print("invalid")

Answer 2

import re

s=str(input())
c=r"(1|8|9)......."

match = re.search(c, s)
if (match and len(s)==8):

print("Valid")
else:
print("Invalid")

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Answer 3

You must using symbol $ :
"[189]\d{7}quot;

Answer 4

import re
#your code goes here
num = input()
pattern = r"(1|8|9)\d{7}quot;
match = re.match(pattern,num)
if match:
print("Valid")
else :
print("Invalid")

Answer 5

A simpler way with 5 lines of code.

A simple explanation, loop through all lines, and if a line has trailing/ending "\n" remove it from the count of the length.

https://code.sololearn.com/cdaPdMWWeN3W/?ref=app

Answer 6

import re

monge=str(input())
gaspar=r"(1|8|9)......."

match = re.search(gaspar, monge)
if (match and len(monge)==8):

print("Valid")
else:
print("Invalid")

Answer 7

Give examples what is needed, and what is done already

Answer 8

For the BOOK TITLE

You have been asked to make a special book categorization program, which assigns each book a special code based on its title.
The code is equal to the first letter of the book, followed by the number of characters in the title.
For example, for the book "Harry Potter", the code would be: H12, as it contains 12 characters (including the space).

You are provided a books.txt file, which includes the book titles, each one written on a separate line.
Read the title one by one and output the code for each book on a separate line.

For example, if the books.txt file contains:
Some book
Another book

Your program should output:
S9
A12

Answer 9

Thanks....

Answer 10

https://www.w3schools.com/JUMP_LINK__&&__python__&&__JUMP_LINK/python_regex.asp
actually I’m still a beginner and i haven’t studied regex module yet but you can try this link (-.-;)y-~

Answer 11

Hi,
I cannot to figure out why fails on test my code...
Any idea?
```
import re
#your code goes here
n = input()
result = re.match("[189]\d{7}", n)
if result:
print("Valid")
else:
print("Invalid")
```

Answer 12

Can anyone help in solving phone number validator program in python

Answer 13

import re
#your code goes here
n=input()
pattern=r"^1|8|9\r[1-9]quot;
match= re.search(pattern,n)
if(match and len(n)==8):
print ("Valid")
else:
print("Invalid")

Answer 14

About that Phone number validator...
What if i want to do it with REGEX....
Because, that was the hint they give...

Answer 15

You are given a number input, and need to check if it is a valid phone number.
A valid phone number has exactly 8 digits and starts with 1, 8 or 9.
Output "Valid" if the number is valid and "Invalid", if it is not.
import re

monge=str(input())
gaspar=r"(1|8|9)......."

match = re.search(gaspar, monge)
if (match and len(monge)==8):

print("Valid")
else:
print("Invalid")

Answer 16

import re

monge=str(input())
gaspar=r"(1|8|9)......."

match = re.search(gaspar, monge)
if (match and len(monge)==8):

print("Valid")
else:
print("Invalid")

Answer 17

# BOOK TITLES
# -------------------
file = open("/usercode/files/books.txt", "r")

lines = file.readlines()
for l in lines:
print(f'{l[0]}{len(l.strip())}')

file.close()

# --------------------------------------------------------

# PHONE NUMBER VALIDATOR
# ^ --> starts with, $ --> ends with
# ---------------------------------------
import re
if re.search('^(1|8|9)\d{7}#x27;, input()):
print("Valid")
else:
print("Invalid")

Answer 18

import re
#your code goes here
number = input()

pattern = r"[1|8|9]+.......quot;

if re.match(pattern,number):
print("Valid")
else:
print("Invalid")

Answer 19

# 8 digit Phone number generator
import re
num = input()
pattern = r"[1|8|9]\d{7}quot;
if re.match(pattern , num):
print ("Valid ")
else:
print ("Invalid")

Good luck to everyone 🙏

Answer 20

And for the PHONE NUMBER VALIDATOR

You are given a number input, and need to check if it is a valid phone number.
A valid phone number has exactly 8 digits and starts with 1, 8 or 9.
Output "Valid" if the number is valid and "Invalid", if it is not.

Sample Input
81239870

Sample Output
Valid