+ 2

how to solve this problem? choose 0 or 2 or 4 to see problem 👇👇👇{ SOLVED }

https://code.sololearn.com/c4qDXnvlLg5X/?ref=app

14th Oct 2020, 4:34 AM
Hassan Raage
Hassan Raage - avatar
4 odpowiedzi
+ 5
Just break the loop after conditions,then it will work fine! https://code.sololearn.com/c892FM9Ffb1V/?ref=app
14th Oct 2020, 4:46 AM
chaithra Gowda
chaithra Gowda - avatar
+ 6
instead of using: if tickets[choose]%2 != 0: .... you could use the membership operator "in": if choose in tickets: ... When using code like you did, and user selects a number that is not in list, you get an index error and program gets terminated.
14th Oct 2020, 10:51 AM
Lothar
Lothar - avatar
+ 5
Hassan 》》 Raage , i forgot something to mention: I assume that you want all odd numbers to make for free, and all even numbers to pay for. In this case you can go an other way: - insted of using a list, you may use a range defined like below: This range has a definition running from 1 (first odd number) up to 9 (but as 9 is not included you take 10), and use a step from number to number of 2. Can you try and give a short feedback if it meets your requirements? When you need to have numbers greater than defined, just modify the second number to your requirements. choose = int(input("Choose item number : ")) while True: if choose in range(1,10,2): print("Free item") break else: print("Price $") break
14th Oct 2020, 11:25 AM
Lothar
Lothar - avatar
+ 3
Lothar Thanks i've change if tickets[choose] to if choose in tickets, thanks a lot
14th Oct 2020, 11:01 AM
Hassan Raage
Hassan Raage - avatar