This is an array stack program. Please help. (Question after code)

Question

#include<stdio.h>
void push(char element, char stack[], int *top, int stackSize){
if(*top == -1){
stack[stackSize - 1] = element;
*top = stackSize - 1;
}
else if(*top == 0){
printf("The stack is already full. \n");
}
else{
stack[(*top) - 1] = element;
(*top)--;
}
}
void pop(char stack[], int *top, int stackSize){
if(*top == -1){
printf("The stack is empty. \n");
}
else{
printf("Element popped: %c \n", stack[(*top)]);
// If the element popped was the last element in the stack
// then set top to -1 to show that the stack is empty
if((*top) == stackSize - 1){
(*top) = -1;
}
else{
(*top)++;
}
}
}
int main() {
int stackSize = 4;
char stack[stackSize];
// A negative index shows that the stack is empty
int top = -1;
push('a', stack, &top, stackSize);
printf("Element on top: %c\n", stack[top]);
push('b',stack, &top, stackSize);
printf("Element on top: %c\n", stack[top]);
pop(stack, &top, stackSize);
printf("Element on top: %c\n", stack[top]);
pop(stack, &top, stackSize);
printf("Top: %d\n", top);
pop(stack, &top, stackSize);
return 0;
}

Here, we add or remove elements in the array stack[] in functions push and pop. How come the the values updated in those functions get updated in the main aswell without using any pointer array or returning anything? it's not even a global variable..

Answer 1

hey Mohammed,
array don't get copied when we passing through a function unlike variables which get copied. An alias is created for the same array which is passing.So the change in the function could get reflected in main function.