Phone number validator

Question

I was able to pass the challenge with this code, but when I test it the code is flawed. I can start with any number and get valid.
https://code.sololearn.com/cX5xUa0DxB2r/?ref=app

Answer 1

Can you share a specific test case that isn't behaving correctly?

"1234abcd" starts with a number and is invalid and the code correctly indicates "Invalid".

"12345678" prints "Valid" which is probably what you want.

This is the code I saw when I clicked your link in case you update it:
import re
num = input()
pattern = r"^{^1|8|9}|{^1-9}"

if re.search(pattern, num) and len(num) == 8:
print("Valid")
else:
print("Invalid")

Answer 2

import re

number = input()

pattern = r"[189][0-9]{7}\Z"

matches = re.match(pattern, number)

if matches:
print("Valid")
else:
print('Invalid')

This works Well

Answer 3

I’ve now fixed the code
pattern = r"^[1|8|9][0-9]{7}quot;

Answer 4

This one got me through.

import re

number = input()
pattern = r"[189]\d{7}quot;
if re.match(pattern, number):
print("Valid")
else:
print("Invalid")

Answer 5

import re
num = input()

pattern = r"^[1|8|9].{7}"
if re.match(pattern, num) and len(num) == 8:
print("Valid")
else:
print("Invalid")

this one was nice and compact

Answer 6

68963279 this prints valid