Java ++ operator

Question

Hey guys. I am a bit confused why x become 4 and not 5 in the code below?

int x =1;
x = ++x + x++;
System.out.println(x);

Answer 1

It’s because the x++ returns x, then makes it higher.
So, ++x will make it higher, and give 2, and x++ will give 2, THEN turn x into 3.
2 + 2 = 4
Hope this helps.

Answer 2

Thanks I got it

Answer 3

I understand that x++ will first evaluate the statement and then add one. In this way 'x' first becomes 2(++x) and then it will be added to x(2+2 =4). Now the assignment is executed so x is 4. BUT after the assignment x++ should add one to x which gives 5. So after the execution of line two, x should be 5 !!! :(