How can a write a FizzBuzz program in Python?

Answer 1

Devansh Jhawar Ok so here's the code:

n = int(input("Enter the ending number: "))

for x in range(1, n):
if x % 3 == 0 and x % 5 == 0:
print("FizzBuzz")
elif x % 3 == 0:
print("Fizz")
elif x % 5 == 0:
print("Buzz")

Hope It helps :)
If you have any queries, feel free to ask...

Answer 2

Khalid Kotte Why is there a continue statement?? There's no Loop in the code! Continue & break statement is used only when in a Loop!!

Answer 3

n = int(input())

for x in range(1, n):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 2 == 0:
continue
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 4

Search the web dude, if you don't wanna write yourself!!!

Answer 5

I'd tried it from days and I'm not getting it right so I'm asking for a help. A small hint would be a great help bro.

Answer 6

Thanks a lot ADVIK for the answer. It truly helped me. I got to know where I was making mistake. Thank you once again

Answer 7

Help me to solve this quiz, it tells me "expected an indented block in line 5"

Answer 8

Thanks Devansh Jhawar

Answer 9

n = int(input())

for x in range(1, n, 2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

#This is the correct answer

Answer 10

print('Enter a number')
n=int(input())

for SoloLearn in range(1,n):
if ((SoloLearn % 3)==0)and (SoloLearn %5)==0):
print("SoloLearn")
continue
elif SoloLearn %3==0:
print("Solo")
continue
elif SoloLearn %5==0:
print("Learn")
else:
print("SoloLearn")