How can 5/2=2 and error divide by 0 at the same time???

Question

In the "Multiple Exceptions" java coach challenge , can any one explain the following:

Test case #1
Input
5
2

My output
2

Expect output
2

Test Case #2
Input
5
2

My Output
2

Expected Output
Error: division by 0
...............................

How can 5/2 be both 2 and error: division by 0 ?????
Please explain.
I get all test cases, but #2. The link to
The code Is

https://code.sololearn.com/cDugQ4EstWIo/?ref=app

Answer 1

Can we see the task what you're trying to do?
Your code is working as expected. I think it's a bug.

Answer 2

I've reported to SoloLearn.

https://www.sololearn.com/learn/Java/2176/

Answer 3

Here is the text of the coach callenge:

Multiple Exceptions 10XPs

You need to write a divider program which will operate with integers,
The program you are given should take two integers as input and execute the division, but we need to handle two exceptions:
1. the divider shouldn't be zero
2. both inputs should be integers.
Complete the program to handle them. For the first exception, the program should output "Еrror: division by zero"; and for the second one, "Error: wrong value type".

Sample Input
1
b

Sample Output
Error: wrong value type

Use ArithmeticException for first exception and InputMismatchException for the second one.