I need help with a pro challenge question.

Question

I need to modify this code to sum all the numbers that are run through the loop starting with the input number.

n = int(input())

length = 0

while n > 0:
n //= 10
length += 1

print(length)

Answer 1

Question is not clear...
Your code does, finding number of digits in input number..
What it means "sum all numbers run through loop"? Do you mean finding sum of all digits of number?
If yes, take another variable, and before n//10 add reminder of n%10 to sum.

sum=n%10
n//=10

print(length, "sum=", sum)

Answer 2

It may be easier in python to just use built-in types and functions to convert to your answer.
For instance to get the length or number of digits entered you could just use len() on the input number.
To get the sum of the individual digits you can convert the input to a list and then map the list to ints then sum() the new mapped list.

input = 12345

print(sum(map(int, list(input()))))

output = 15

Answer 3

Jayakrishna🇮🇳 Awesome that solved it! But could you explain how this works? I’m not understanding what n//10 is doing and how this outputs to the correct output

Answer 4

If input n = 1234
sum=0
1) sum+= n%10 = 1234%10 => sum=4,
n = n//10=>n=1234//10=> n= 123

2) sum+= n%10 = 123%10 => sum=4+3=7,
n = n//10=>n=123//10=> n= 12

3) sum+= n%10 = 12%10 => sum=7+2=9,
n = n//10=>n=12//10=> n= 1

4) sum+= n%10 = 1%10 => sum=9+1=10,
n = n//10=>n=1//10=> n= 0

n>0 false, so loop stops now, sum =10, length=4, n=0
Hope it clears.. Kevin Grothe