Python question/problem (range)

Question

You are making a date picker for a website and need to output all the years in a given period.
Write a program that takes two integers as input and outputs the range of numbers between the two inputs as a list.
The output sequence should start with the first input number and end with the second input number, without including it.

Sample Input
2005
2011

Sample Output
[2005, 2006, 2007, 2008, 2009, 2010]

My code is

A = int(input())
B = int(input())
number = list(range(1,10))
print (numbers)

Answer 1

If you observe output of your code, you can find what is needed solution.. Here is solution...

Read about range() function for more info...

numbers = list(range(A, B))
print(numbers)

Answer 2

the answer you've been waiting for

a=int(input())
b=int(input())
numbers=list(range(a,b))
print(numbers)

Answer 3

Yazan , there are several issues in the code:

- the range you create does give 10 numbers 1,2,..., but you should generate the years instead. So use A and B to create the range
- print() has an indentation that is not correct here
- print(numbers) does create an error, as numbers is not defined. correct name is number

Answer 4

Here is my code

a = int(input())
b = int(input())
years = list(range(a, b))
print(years)

Answer 5

a = int(input())
b = int(input())

years = list(range(a,b))

print(years)

Answer 6

a = int(input())
b = int(input())
years = list(range(a, b))
print(years)

done...!

Answer 7

s=int(input('enter the start value of year: '))
e=int(input('enter the end value of year: '))
l=[]
while(s<e):
l.append(s)
s=s+1
print(l)

very simple code

Answer 8

#Also
lower_bound = int(input())
upper_bound = int(input())

print(years_list := list(range(lower_bound, upper_bound)))

Answer 9

Check this out;

a = int(input())
b = int(input())
c = list(range(a,b))
print(c)

Answer 10

This is the proper solution to this exercise:

a = int(input())
b = int(input())
#your code goes here
years = list(range(a, b))
for x in years:
print(years)
break

Answer 11

a = int(input())
b = int(input())
yea=list(range(a, b))
for x in yea:
print(yea)
break

Answer 12

a = int(input())
b = int(input())
years = list(range(a, b))
print(years)

Answer 13

a = int(input())
b = int(input())
dates= list(range(a, b, 1))
print(dates)

Answer 14

a=int(input())
b=int(input())
numbers=list(range(a,b))
print(numbers)

Answer 15

a = int(input())
b = int(input())
list = list(range(a,b))
print(list)
This is the suitable answer for this program and make sure pls right this program as same as written.

Answer 16

a = int(input())
b = int(input())
list1=[]
for i in range(a,b,1):
list1.append(i)

print(list1)

Answer 17

a = int(input())
b = int(input())

x = list(range(a,b))
print(x)

Answer 18

a=int(input())
b=int(input())
for i in range(a,b):
print(i)