Please what can I do to make the program as for another input after the first one has been inputed.

Question

print("menu")
print("Enter records")
print("see statistics")
print("List all records")
print("Quit")
print("..........................")
x = int(input())
if x == 1:
print("Enter records")
elif x ==2:
print("See statistics")
elif x ==3:
print("List all records")
elif x == 4:
print("Quit").....
I know it's a loop but I dunno how or where to write it so it can ask for another input so the user can select...pls help this is in python thanks

Answer 1

You need a while loop. Basically, you need to keep asking for x until the user enters Quit, so you can do something like this:

While True:
x = int(input())
If x == 'Quit':
break

You can put the rest of your code below that.

Answer 2

Ok so pls show me an e.g using my code above

Answer 3

Well, you can start the while loop either right above all of your code to print the menu options after each iteration or you can start it right before asking for x so you can ask the user to input on each iteration but not printing the menu options every time

Answer 4

Great you understand.
Now my problem is how do I write it
What position do I put the while loop

Answer 5

David Solomon Put the while loop before the part of the code you want to loop. (e.g.
while True:
(Tab) input("? ")
)