Can anyone solve it?

Question

I have a pattern output
1
11
112
1123
11234
112345

Answer 1

Rajdeep Mazumdar Yes but you need to try first.

Answer 2

Brian You missed to add one line before the loop. 🤪

cout << pattern << endl;

Answer 3

#include <iostream>
using namespace std;

int main()
{
int i,j,n,k=1;
cout<<"Enter the value of n"<<endl;
cin>>n;
for(i=0;i<=n;i++)
{
cout<<k;
for(j=1;j<=i;j++)
cout<<j;
cout<<endl;

}
return 0;
}
i tried it it's right but i want another way

Answer 4

Here is another way. Build the output string and print it incrementally.

#include <iostream>
using namespace std;

int main()
{
int i, n;

cout << "Enter the value of n" << endl;
cin >> n;

string pattern = "1";
cout << pattern << endl; // Edited
for (i = 1; i<=n; i++) {
pattern += to_string(i);
cout << pattern << endl;
}

return 0;
}

Answer 5

Good catch, I Am Groot !

Initially I wrote two loops, one to generate the last string with all the numbers, and one to print pattern.substr(0,i) per row (i=1 to pattern.size). Then I discovered a minor problem. When i=10 it printed "...7891" and then "...78910", instead of only "...78910". Combining the loops corrected it, but I had overlooked the initial row.

I added your correction. Thank you.

Answer 6

It's not Fibonacci

Answer 7

If u observe it carefully it's a Fibonacci triangle starting with 1 . So at the end u have to write the value as 1 instead of 0

Answer 8

Atul Panda I agree there is a strong correlation with the Fibonacci sequence. But then the 4 breaks the pattern.

Rajdeep Mazumdar, is 4 really part of the sequence, or is it a typographical error?

Answer 9

Brian I know but it's possible but it's bit tricky too. But I really esteem your words because I don't have experience with c++. If it would have been java then I should have solved it and sent it to the required person

Answer 10

Coder/Christmas Kitten I like your use of memoization to avoid unnecessary recursion in Fibonacci!