How to enter list of given range of elements at a time,plz check description

Question

L=[int(x) for x in input().split()]
-->any number of integers intake
But i want to take elements according to user requirement like
L=[int(x) for x in range(6).input().split()]-->but its not working

Answer 1

As you want your L list to be int you can just add [:6] after split function in your solution
L=[int(x) for x in input().split()[:6]]

Answer 2

if suppose you provide your input data may be we could get a clear understanding about the issue

Answer 3

the thing is you don't need a loop for this input.
you can use a slice operation for this like
L=input ().split()[:6]

Answer 4

you mean like six different list of numbers?

Answer 5

S,6 different integers in same list

Answer 6

maybe you can try using two for loops like

L=[[int(y) for y in input().split()] for x in range(6)]

Answer 7

Iam getting error message

Answer 8

what error message

Answer 9

mylist = [int(input()) for x in range(6)]
print(mylist)

# or
size = int(input())
mylist = [int(input()) for x in range(size)]
print(mylist)

You can also use an underscore instead of the 'x' above.

Answer 10

Sathish Kanna once try to execute it

Answer 11

rodwynnejones u haven't used split function

Answer 12

I/p:-5 2 0 8 9 0
Ur approach is correct but it is showing EOF error

Answer 13

Give example input.

Answer 14

Thank u Sathish Kanna rodwynnejones