C++ in the exercise ticket office

Question

I am doing the exercise ticket office and I am wondering if there is an official solution because I think that pointers can play a part in this exercise but my solution includes only if statements(the most)

Edit
Here is my attempt:
#include <iostream>
using namespace std;

int main() {
int ages[5] = { 100,100,100,100,100 };
int ticket = 10;
int tempAge = 0;
double minAge = 100;
double finalPrice = NULL;
for (int i = 0; i < 5; ++i) {
cin >> ages[i];

tempAge = ages[i];
finalPrice = finalPrice + ticket;
for (int x = 0; x < 5; ++x) {
if(tempAge < ages[x] && tempAge < minAge){
minAge = tempAge;

}

}

}
cout << finalPrice - (finalPrice * (minAge / 100));

//your code goes here

return 0;
}
*I thought pointers would be in need but I didn't need them and don't quite understand their use (except for freeing ram after the purpose of a variable is completed)

Answer 1

Pointers are not needed in this exercise. It is more about data types, loops, arrays, and calculations - everything up until the pointers lessons.

Answer 2

use this
i guarantee it will work
please upvote me

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
int n = sizeof(ages)/sizeof(ages[0]); int minimum = ages[0]; for(int i=0; i<n;i++) { minimum = min(minimum, ages[i]); } double d = 50*(minimum/100.00); double total = 50 - d; cout<<total;
return 0;
}