+ 3
List String To List Name
Say I Have: import random rint=random.randint list=["ABC","BCD","CDE"] ABC=["1", "2"," 3"] main=list[rint(0,0)#Usually Would Be 0,2 but to make example easy to understand it will be 0,0 sub=main[rint(0,0)] print(main)#Prints out "ABC" print(sub)#Prints out "A" Output is: A Wanted Output: 2 How can I get the output as "1" from the list ABC instead of "A" from the list item? Sorry if it doesn't make sense I don't really know how to explain it that well.
6 odpowiedzi
+ 9
# There's many ways to do it, with nested list in dict ( I guess your first list contain other same kind of name lists ):
list = ["ABC","BCD","CDE"]
dict = {"ABC":["1","2","3"],"BCD":["4","5"],"CDE":["6","7"]}
x = dict[list[0]]
print(x[1])
# ... and, if you want to lighten notation, use a function:
_list = ["ABC","BCD","CDE"]
dict = {"ABC":["1","2","3"],"BCD":["4","5"],"CDE":["6","7"]}
def list(index):
global dict
return dict[list[index]]
x = list(0)
print(x[1])
# ( according to your needs, you can use global and/or local variables, obviously ^^ )
+ 7
I'm happy if this help: I've seen only after you've updated your question ^^
Be carreful: as I read too fast first your new example code, I didn't see that you define a 'rint' custom variable with the 'randint' function, so while searching what would do this function on internet, I find that a rint() function exists in numpy library... It doesn't matter a lot, but you need to know that if you'll have to use this module ;)
+ 1
if you want x to have the values of ABC then have x = ABC rather than x = list.
Or maybe I'm misunderstanding the question.
+ 1
@Jason Williams Yes, it seems you misunderstood my question but now I've updated it
+ 1
Thank You Very Much @visph I've been trying to figure this out for so long (since this morning :P) Thank You Very Much For The Spread Of Your Knowledge And Your Amazing Solution!
- 1
list = ["ABC","BCD","CDE"]
dict = {"ABC":["1","2","3"],"BCD":["4","5"],"CDE":["6","7"]}
x = dict[list[0]]
print(x[1])
# ... and, if you want to lighten notation, use a function:
_list = ["ABC","BCD","CDE"]
dict = {"ABC":["1","2","3"],"BCD":["4","5"],"CDE":["6","7"]}
def list(index):
global dict
return dict[list[index]]
x = list(0)
print(x[1])