Problem with scanner.nextInt in do-while loops

Question

Hi everybody,

i'm currently working on the "Do-while" test with the call center. I just can't seem to figure out how to print the string e.g. 1 for Language support.

I can get my code to enter any number and keep it going until the user enters "0".
I really thought that I had cracked it, but it doesn't work...

Would appreciate any help!

import java.util.Scanner;
public class DoWhile {
public static void main(String[] args) {
Scanner scanner = new Scanner (System.in);
int nummber = scanner.nextInt();
do {
number = scanner.nextInt();
if (number == 1){
System.out.println ("Language selection");
if (number == 2);
System.out.println("Customer support");
if (number == 3)
System.out.println("Check the balance");
if (number == 4)
System.out.println("Check loan balance");
if (number == 0)
System.out.println("Exit");
}
} while(number !=0);
}
}

Answer 1

I made this if you get confused about anything just ask 👍

https://code.sololearn.com/caj7RiiAjgsg/?ref=app

Answer 2

variable naming error
braces missing on for loops
if and else statements should be used

https://code.sololearn.com/cnCAY6gxW3PX/?ref=app

Answer 3

thank you so much! It all make sense. As you said in the first comment I didnt use the else if statements. Furthermore I didnt think of using a boolean value.
Appreciate your willing to help a beginner like me 🙏

Answer 4

Binh Tan Nguyen no probelm 👍👍

Answer 5

Okay with a fresh mind this morning I was able to figure this out, now boolean needed. The main issue I had is as someone stated, the scanner input needs to be assigned IN the do while statement, so it can take a new input each time. Also, i remembered that the first line after the while requirement is printed when the while requirement is not met. So when the input is 0, the while requirement fails, and the first line after is printed, in this case "Exit".

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int number;
do {
number = scanner.nextInt();
if (number == 1){
System.out.println ("Language selection"); }

else if(number == 2){
System.out.println("Customer support"); }

else if(number == 3){
System.out.println("Check the balance"); }

else if(number == 4){
System.out.println("Check loan balance"); }
}
while(number != 0);
System.out.println("Exit");

}
}

Answer 6

D_Stark

I still can't seem to run the code accordingly... This is the problem description:

You are creating an automated phone system for bank clients.
Number selections should activate the actions noted below as follows:
1 => Language selection
2 => Customer support
3 => Check account balance
4 => Check loan balance
0 => Exit

You can use the first 4 commands in a random sequence without interrupting the phone call - only the number 0 does.
Write a program that will continuously take a number as input and output the corresponding message, until the client enters 0.

Sample Input
1
4
3
0

Sample Output
Language selection
Check loan balance
Check the balance
Exit

Answer 7

D_Stark. Forgive my ignorance. But I'm having trouble understanding what purpose the boolean serves? I am currently having issues with this problem myself. Complete newbie to coding.

Answer 8

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

do{

int x = sc.nextInt();

if(x == 1){System.out.println("Language selection");}

else if(x == 2){System.out.println("Customer support");}

else if(x == 3){System.out.println("Check the balance");}

else if(x == 4){System.out.println("Check loan balance");}

else if(x == 0){System.out.println("Exit");}

else{ }

} while (sc.hasNextInt());

}

}