What is the mistake in this code ? Why I am not geting the desired output?

Question

import random

def myattack() :
ketondamage = ["Keton dodge your attack","30 % damage to keton","10 % damage to keton","Critical 70 % damage to keton"]
m = random.choice(ketondamage)
print(str(m))
if str(m) == ketondamage[0]:
print("[//////////]")
elif str(m) == ketondamage[1]:
print("[///////]")
elif str(m) == ketondamage[2]:
print("[/////////]")
elif str(m) == ketondamage[3]:
print("[///]")
else:
print("error")

myattack()

Output :-
Traceback (most recent call last):
File "source_file.py", line 7, in <module>
if str(m) == ketondamage[0]:
NameError: name 'm' is not defined
Process finished with exit code 1.Traceback (most recent call last):
File "v.py", line 7, in <module>
if str(m) == ketondamage[0]:
NameError: name 'm' is not defined
Process finished with exit code 1.

Answer 1

Its python bro . Here everything depends on indention. Cheque your indention of If elif else statement they aren't at proper level

See the fixed code \/

import random

def myattack() :
ketondamage = ["Keton dodge your attack","30 % damage to keton","10 % damage to keton","Critical 70 % damage to keton"]
m = random.choice(ketondamage)
print(str(m))
if str(m) == ketondamage[0]:
print("[//////////]")
elif str(m) == ketondamage[1]:
print("[///////]")
elif str(m) == ketondamage[2]:
print("[/////////]")
elif str(m) == ketondamage[3]:
print("[///]")
else:
print("error")

myattack()

Answer 2

Better to use dictionary.
keton = {
"critical": 0.7,
" casual": 0.1,
"dodge": 0.3
}
def keton_attack(x):
a =random.coice(x)
print(x[a])
keton_attack(keton)