Evaluating a falsy value in JS.

Question

Let's say I have a boolean variable called:
let gameOver = false;
My question is, if I want to evaluate the gameOver variable like this:
if (!gameOver) {...}
¿What exactly I'm evaluating? ¿If the variable gameOver is false?

Answer 1

Yes, you would be saying "If the game is not over..." because this will first check the value of gameOver, and then reverse it, so that if it is true, it will return false and if it is false, then it will return true.
Then, the if statement checks if the result of the operation was true and if it was, execute the code below.

Another way of seeing it is:
gameOver = false = gameOver is equal to true = false
!gameOver = true = not gameOver is equal to true = true because gameOver is false

if not (gameOver is equal to true), then execute some code, otherwise don't.

I hope this clarifies things!!

Answer 2

!true is always false and !false is always true.
So if `gameOver` is true, !gameOver will be false and the if-block will not be executed. It's the complete opposite if `gameOver` is true

Answer 3

!gameOver <=> gameOver==false

return true for any falsy value (including undefined, null, 0...)