Working with NUMBERS[SOLVED]

Question

#given a number
N=int(input())
#I want to check if it is divisible for another number n (example N=20, n=3)
Rem= 20%3 - >2
#NOW, I want to add to N that number which makes the remainder =0.
#If I add the Rem to N I still get (20+2 %3 - >1) How can I do it? Thanks

Answer 1

Add n - rem to N to get N%n as 0

Answer 2

You need a condition, if it has remainder then N is not divisible by n, if the remainder is 0 then N is divisible by n.

For example:
20 % 3 == 2

This has remainder 2 therefore 20 is not divisible by 3.

21 % 3 == 0

This has no remainder therefore 21 is divisible by 3.

Answer 3

Subtract instead of adding

Answer 4

Sorry I forgot to mention that n is fixed and I can only increase N

Answer 5

You should either subtract the reminder or add its additive inverse

if a = b(mod n) than a-b=0(mod n)
The same way as
if a=b than a-b=0