Gan i have your help I'm having trouble with this

Question

You are making a program to analyze text.
Take the text as the first input and a letter as the second input, and output the frequency of that letter in the text as a whole percentage.

Sample Input:
hello
l

Sample Output:
40

The letter l appears 2 times in the text hello, which has 5 letters. So, the frequency would be (2/5)*100 = 40.

Answer 1

text=input()
letter=input()
x=text.count(letter)
print(int((x/len(text))*100))

This also gives correct output!!!!

Answer 2

#your code goes here

string = input("")
string1 = input("")

number = 0

i = string1

for i in string:
if i == string1:
number += 1

#print(number)

len = len(string)

calc = number/len*100
print(int(calc))

#Thia code worked for me I hope that this helps You

Answer 3

Answer

text = input()
letter = input()

text_count = 0
letter_count = 0

for i in text:
text_count += 1
for i in text:
if letter == i:
letter_count += 1
letter_percentage = (letter_count/text_count)*100
print(int(letter_percentage))

Answer 4

like (:

text = input("") # hello
letter = input("") # l
count = text.count(letter) # 2
length = len(text) # 5
calculate = (count / length) * 100
print(int(calculate))

Answer 5

#your code goes here
string = input("")
string1 = input("")

number = 0

i = string1

for i in string:
if i == string1:
number += 1

#print(number)

len = len(string)

calc = number/len*100
print(int(calc))

for any answer follow me on sololern

Answer 6

string = input("")
string1 = input("")
count = 0

i = string1
for i in string:
if i == string1:
count+=1
length = len(string)
freq = (count/length)*100
print(int(freq))

try to get this code ;) , it is easy
HAPPY LEARNING :)

Answer 7

x = input()
y = input()
#length of full character
full = len(x)
#counting how many times the character has appeared
single = (x.count(y))
print(int((single/full)*100))
# this code will give you the perfect output

Answer 8

text = input()
letter = input()
Freq = text.count(letter)
ltext = len(text)
Frequency = int((Freq / ltext) * 100)
print(Frequency)

Answer 9

text=input()
letter=input()
count=text.count(letter)
lenght=len(text)
print(int(count/lenght*100))

Answer 10

Please post your attempt also.

Answer 11

try this code it works for me

word = input()
char = input()
result = (word.count(char)/len(word))*100
print(int(result))

Answer 12

string = input()
letter = input()
count = 0
string = string.upper()
letter = letter.upper()

for i in string:
if i == letter :
count += 1

frequency = int((count/len(string))*100)

print(frequency)

This is the answer and you can take out the two lines after count if you want to. They are redundant. However, I used it to make it a perfect code that returns no issue.

Answer 13

#your code goes here
str = input()
letter = input()
freq = (str.count(letter)/len(str))*100
print(int(freq))

Answer 14

#your code goes here

text = input()
letter = input ()

result = (text.count(letter)/len(text))*100
print (int(result))

Answer 15

text=input()
letter=input()
x=text.count(letter)
print(int((x/len(text))*100))

Answer 16

x = input()
y = input()

a = x.count(y)
b = len(x)

c = a/b*100

print(int(c))

Answer 17

This worked for me!

word = str(input())
letter = str(input())
count = word.count(letter)
print(int((count/len(word))*100))

Answer 18

x = str(input())
y = str(input())
print(int(x.count(y) / len(x) * 100))

Answer 19

try this solution

x = str(input())
y = str(input())
v = x.count(y)

w = len(x)
a = v/w
b = a*100
print(int(b))

Answer 20

x = input()
y = input()

print (int((x.count(y)*100/len(x))))

people like to overcomplicate things here