Why too many charecters are printed ?!

Question

Guys i have this problem plz help me
#include <iostream>
using namespace std;

int main() {
string a; cin>>a;
char b=a[0];
for(int i=1; i<=b; i++){
cout<<a[0];

}
return 0;
}
Suppose that i entered 567 , then i expect to print number 5 , 5 times . While it prints it too many times , why?

Answer 1

when in " i<=b " i is compared with b , b value is casted to int type which is 53(ascii value) for character '5'.

you should rather look into doing something like the following ,

int main() {
string a;
cin>>a;

string c(1,a[0]);
int b=stoi(c);

for(int i=1; i<=b; i++){
cout<<a[0];

}
return 0;
}

string constructor converts the above char a[0] to string first using "string c(1, a[0])

now you have a string "5" you can convert it to integer using "stoi" function.

There are many other ways to convert character to string if above is confusing , so take a look at the article for better understanding of above method and various other ways.

https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.geeksforgeeks.org/how-to-convert-a-single-character-to-string-in-cpp/amp/&ved=2ahUKEwiIpcCMkPPuAhWfxTgGHW6lB4gQFjAAegQIBBAD&usg=AOvVaw1cQJIG9c_IEOhcI4-Mdvm5&ampcf=1

Answer 2

Abhay Thank you so much for making me aware of this point😊👍