Invalid sintax - Line 8

Question

weight = 85
height = 1.9
BMI = (float(weight / height**2))

if BMI < 18.5:
print("Underweight")
else:
if BMI >= 18.5 and < 25:
print("Normal")
else:
if BMI >= 25 and < 30:
print("Overweight")
else:
if BMI >=30:
print("Obesity")

Answer 1

So here we go:

weight = int(input())
height = float(input())
BMI = (weight / height**2)

if BMI < 18.5:
print("Underweight")
elif BMI >= 18.5 and BMI < 25:
print("Normal")
elif BMI >= 25 and BMI < 30:
print("Overweight")
elif BMI >=30:
print("Obesity")

Answer 2

When you use "and" operator, you have to write comparable variable again

Answer 3

in python you could also write:

if 18.5 <= BMI < 25:

to test if a value is in a range ;)

Answer 4

Nazeekk
No ways,
I had solved this.
In python beginners course.
ok

Answer 5

... and BMI < 25

Answer 6

also, as you first test for lowest bound, next you don't have to test for it:

So here we go:

weight = int(input())
height = float(input())
BMI = (weight / height**2)

if BMI < 18.5:
print("Underweight")
elif BMI < 25: # necessarly BMI >= 18.5
print("Normal")
elif BMI < 30: # necessarly BMI >= 25
print("Overweight")
else: # necessarly BMI >= 30
print("Obesity")

Answer 7

Sathe Prerana Satish
I mean, you just copied my answer😳😳

Answer 8

Davide Calanna

Try this:

#your code goes here
weight = int(input());
height = float(input());
bmi = weight/float(height*height);
if bmi<18.5:
print('Underweight')
elif bmi>=18.5 and bmi<25:
print("Normal")
elif bmi>=25 and bmi<30:
print('Overweight')
else:
print('Obesity')