If java not have operator overloading how can this work

Question

If java don't have operator overloading so how

("java" + 10 ) return "java10"

If any one this plz.. answer me...

Answer 1

This can be done i.e. with overloading of methods as here:

https://code.sololearn.com/cRTA1it71ioT/?ref=app

Answer 2

ive read about this before
when we do smth like
String a = "a" + 2;
the compiler use string builder to create the string..and if it found integer, it will create the integer and use tostring(idk its name) method and use append method to add that to the string
idk if its true though

Answer 3

Sandeep Jadam don't really have any idea about c++ or java , but python does provide a way to overload operators.

but if i am not wrong these languages internally have a predefined implementation of how to handle all this ( never went into details), and probably operator overloading is way to define custom implementation by the user.

anyway, Just wait for other's answer :) .

Answer 4

Yo... Python bro... Really java and c++ concepts really bad.
Python is simple.

Answer 5

Java has built-in features of adding string with integer.

In c++ we have liberty to tweak the operator to convert explicitly it's also called extendabilty and flexibility to change normal expression using operator overloading.
It is a feature not a concept c++ Opps concept and it has command over language and on contradictory it takes time to evolve. it's very complex to workout in c++.

Python too have operator overloading with class only built-in operators are rigid, means it cannot change.

Have a nice time to understand the terms in all languages.

DHANANJAY

Answer 6

With "Java"+10 the engine interpret that + as a string concatenation

But if you 10+"Java", an exception is thrown because expect doing the sum

So the order is important!

Happens the same operating numbers of different type. Put always the first there store more bits: double->float->long->int->short->byte. Reversing a lossly precission error is thrown if you dont cast types.

Answer 7

That is not operator overloading , that is implicit type conversion happening , java is converting 10 to string when either of the both operand is a string .

https://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html

Answer 8

Bro i know that but i my question is how java define that functionality. If both right and left integer. + operator add but when class + int without operator overloading how can this posible.

Have you ever learn operator overloading in other language like c++ or python3

Answer 9

Yeah it's one way to workout in java with overloaded methods so that you can implement desired flow, when you look at the code it's difficult to grasp.

DHANANJAY