How to make a code for sum of consecutive numbers

Question

Sum of Consecutive Numbers

Take a number N as input and output the sum of all numbers from 1 to N (including N).

Sample Input 100

Sample Output 5050

Explanation: The sum of all numbers from 1 to 100 is equal to 5050.

You can iterate over a range and calculate the sum of all numbers in the range.

Remember, range(a, b) does not include b, thus you need to use b+1 to include b in the range.

Answer 1

N = int(input())
count = N
x = range(1, N +1)
for i in x:
N = i + N
print(N - count)

Answer 2

Sum of Consecutive numbers

N=int(input ())
sum=0
for i in range(1, N+1) :
sum=sum+i
print(sum)

Answer 3

Hints:

** List has a built in sum() function .

** range(int(input())+1) will return a range from 0 to input.

** Now use the sum() function .

** remember sum() is a function of list object not of range so you need to typecast range to list.

Answer 4

here is a list comprehension that would work and below that is a pure math option i saw from a similar post.

N = int(input())
total = sum([sub for sub in range(1, N+1)])
print(total)

here is a pure math method.

N = int(input())
total = (N*(N+1)//2)
print(total)

Answer 5

print(sum(range(int(input()) + 1)))

Answer 6

Simple solution without loop:

a = N+1
print(sum(range(a)))

Answer 7

I used this and it passed:

N = int(input())
nums = (N*(N+1)//2)
print(nums)

Answer 8

N = int(input())
#your code goes here
i = 0
sum = sum(range(i, N))
print (sum + N)

Answer 9

n = int(input())
x = 0
for i in range(1,n+1):
y = x+i
x+=i
print(y)

Answer 10

N = int(input ())
s = 0
for i in range(s, N+1) :
s += i
print(s)

Answer 11

Hi! Here are some examples:

https://code.sololearn.com/cjrtDK1l5uiC/?ref=app

Answer 12

N = int(input())
a = list(range(0,N+1))
Total = sum(a)
print (Total)

Answer 13

N=int(input("Enter your number:"))
x=0
for i in range(1,N+1)

Answer 14

N = int(input())
yeet = N
zep = range(1, N+1)
sum = 0

for num in zep:
sum += num

print(sum)

Answer 15

N = int(input())

list = []

for i in range(1, N + 1):
list.append(i)
print(sum(list))

Answer 16

Sum of Consecutive Numbers

Take a number N as input and output the sum of all numbers from 1 to N (including N).

Sample Input 100

Sample Output 5050

Explanation: The sum of all numbers from 1 to 100 is equal to 5050.

You can iterate over a range and calculate the sum of all numbers in the range.

Remember, range(a, b) does not include b, thus you need to use b+1 to include b in the range.

Answer 17

N = int(input())
sum= int(n*(n+1)/2)
print(sum)

Answer 18

print(sum(range(1, N+1)))

I was overthinking it but ended up with this one-liner and it worked lol

Answer 19

N = int(input())
total = 0
for i in range(0, N):
total += i
print(total + N)