Creating and writing files in java

Question

I have to output three task, but I don't how. Can someone tell me? (pls, write down the missing code)
import java.io.File;
import java.util.Scanner;
import java.util.Formatter;

public class Main {
public static void main(String[ ] args) {
Scanner input = new Scanner(System.in);
try {
Formatter f = new Formatter("tasks.txt");
int count = 0;
while(count < 3) {
//your code goes here
count++;
}
f.close();
}
catch (Exception e) {
System.out.println("Error");
}
readFile();
}

public static void readFile() {
try {
File x = new File("tasks.txt");
Scanner sc = new Scanner(x);
while(sc.hasNext()) {
System.out.println(sc.next());
}
sc.close();
}
catch (Exception e) {
System.out.println("Error");
}
}
}

Answer 1

int result = 100;
f.format("task result %d\n", result);

https://docs.oracle.com/en/java/javase/15/docs/api/java.base/java/util/Formatter.html

Answer 2

import java.io.File;
import java.util.Scanner;
import java.util.Formatter;

public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
try {
Formatter f = new Formatter("tasks.txt");
int count = 0;
while (count < 3) {
String task = input.nextLine();
f.format("%s%n", task);
count++;
}
f.close();

File x = new File("tasks.txt");
Scanner sc = new Scanner(x);
while (sc.hasNext()) {
System.out.println(sc.nextLine());
}
sc.close();
} catch (Exception e) {
System.out.println("Error");
}
}
}

Answer 3

did you find the answer?

Answer 4

The Scanner input has to be passed as a string in the while loop. So:

//add to while loop
String in = input.next();
f.format(in + " \n");

Answer 5

My answer Working

//CODING BY PYSCODES
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String[] inputs = new String[3];

// Read three inputs
for (int i = 0; i < 3; i++) {
inputs[i] = scanner.nextLine();
}

// Print the inputs
for (String input : inputs) {
System.out.println(input);
}

scanner.close();
}
}