Hey guys, i saw this code in a challenge and I can't understand the (*(*(arr+1))) part, I'll be thankful if someone explain it ❤

Question

Arr x Pointer problem
https://code.sololearn.com/c7OhgQzRadS9/?ref=app

Answer 1

its a reference to the first value of the second "row" of data.

if the array is:

{2,3,4,
5,6,7}

and if *(arr) is equal to the entire first row, then *(*(arr)) would be the first value of the first row

Answer 2

No problem! And i know its for c, but pointers are pointers. Check this out if you have some questions

https://www.sololearn.com/learning/2933/

Answer 3

Slick I'll sure do! Thanks again 🙏🏻

Answer 4

Slick --> Your explanation of that output is not a part of that lesson you are pointing to, but it's the same as using this method:

The first element from the second dimension.....

printf("%d", arr[1][0]);

The array is also confusing, because it stands out as the input is in one dimension and not two.

Answer 5

Now, I know how that pointer access to multi arrays works...

cout<< (*(*(arr+1)+1));
//The second element from the second dimension

cout<< (*(*(arr)+2));
//The third element from the first dimension

Answer 6

The output seems to be the sum of rows and columns in the multi-dimentional array.

Answer 7

Quantum Great 😅but can you explain the mechanism of it, just a little bit?

Answer 8

Slick thanks That's so Helpful! Thanks alot 🤩👌🏻