a=2;b=3;c= Find the value of X In all the sentences, as follows X=a*b*a-(b+c/a) X=a mod 100 X=a mod b mod c X= c*c*b\2 + 5

Question

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Answer 1

in c language u can get X value for each instruction like this 🤷‍♂️ :

#include <stdio.h>

int main() {
 int a=2,b=3,c=2;
//set C value

float X;
X=a*b*a-(b+c/a);
printf("\nX=%f",X);
X=a%100;
printf("\nX=%f",X);
X=a%b%c;
printf("\nX=%f",X);
X= c*c*b/2 + 5;
printf("\nX=%f",X);
return 0;
}

Answer 2

I think you have posted your assignment unknowingly.
And c = ?
question is not clear.
language isn't mentioned.

Answer 3

I'm sorry part of the question was missing, ha ha the right question

Answer 4

a=2;b=3;c=1

value of X In all the sentences, as

X=a*b*a-(b+c/a)
X=a mod 100
X=a mod b mod c
X= c*c*b\2 + 5
X= b/(b-(c-1))
X =36758 mod 10
X= b/b mod c
X=b+a+c\2

Answer 5

like this ?
#include <stdio.h>

int main() {
 int a=2,b=3,c=1;

float X;
X=a*b*a-(b+c/a);
printf("\nX=%f",X);
X=a%100;
printf("\nX=%f",X);
X=a%b%c;
printf("\nX=%f",X);
X= c*c*b/2 + 5;
printf("\nX=%f",X);
X= b/(b-(c-1));
printf("\nX=%f",X);
X =36758 % 10;
printf("\nX=%f",X);
X= b/b % c;
printf("\nX=%f",X);
X=b+a+c/2;
printf("\nX=%f",X);
return 0;
}

result :
X=9.000000
X=2.000000
X=0.000000
X=6.000000
X=1.000000
X=8.000000
X=0.000000
X=5.000000