Question from challenge

Question

Why answer of this code is 2?

Code:
if 1&2:
print(1)
else:
print(2)

Answer 1

& is the bitwise AND operator. It checks whether the binary representation of the LHS operand has the RHS operand bit set.

An example with 4 bits values
BINARY DECIMAL
0001 1 (LHS operand)
0010 2 (RHS operand)
----------------- &
0000 0 (result)

Bitwise AND operator checks and sets the bit in the (result) to 1 when the bit (at the same offset) taken from LHS and RHS operand were non zero.

Since the evaluation (result) yields 0 (a falsey value), the execution flow enters the `else` block rather than the `if` block.

Note:
LHS = Left Hand Side
RHS = Right Hand Side

LHS operand is the thing we see to the left of the operator, and RHS operand is the thing we see to the right of the operator.

Answer 2

Ipang Thanks for the explanation

Answer 3

No problem 👌