+ 5
How to check users click on screen (X and y ) using canvas?
No code~
22 odpowiedzi
+ 5
https://code.sololearn.com/WNnT7t33cafL/?ref=app
Made this a while ago
It's simple and does exactly what you need and should be pretty easy to copy and learn from
+ 3
𝕄𝕚𝕔𝕙𝕒𝕖𝕝 𝕃𝕚𝕦 [🄰🄲🅃🄸🅅🄴] (っ◔◡◔)っ Ok I will add some comments to it now
+ 2
Daniel Briceño what do you mean?
+ 2
Ok and can you make an example code? Plz, Daniel Briceño
+ 2
Daniel Briceño yes, canvas
+ 2
Like I don't understand this
document.getElementById('x-value').textContent = e.x;
document.getElementById('y-value').textContent = e.y;
$("#player").css("transform","translate3d( " + e.x/1.5 + "px, " + e.y/1.5 + "px, 0px)");
});
Can you like make it normal canvas no simple? Like no # and e.x and more...
+ 1
Hard. No code. Just HTML?
+ 1
Daniel Briceño no. That is not what I want, plz delete your answers to make this question unanswered.
+ 1
.... Is "JS" allowed?
+ 1
𝕄𝕚𝕔𝕙𝕒𝕖𝕝 𝕃𝕚𝕦 [🄰🄲🅃🄸🅅🄴] (っ◔◡◔)っ My code should work with canvas but if not I can help you adapt it if you DM me
+ 1
Pieter Edwards I was wrong. But that's how you learn.:)
+ 1
Pieter Edwards can you make the code simpler? It is a bit hard to understand in the js.
+ 1
So basically
e.x = The X axis co-ordinate
e.y = The Y axis co-ordinate
The document.getElementById bit is just making it so the X and Y co-ordinate is printed onto the page so is not necessary. Hope you understand now?
+ 1
Pieter Edwards Try to use just JS please. JS must be taught first and then Jquery
+ 1
Pieter Edwards can you use js? No jQuery
+ 1
X = e.clientX-cnv.offsetLeft
Y = e.clientY-cnv.offsetTop
check line 29 & 30
where cnv is the canvas element.
https://code.sololearn.com/W6d0E0j5wCMB/?ref=app
0
In a course that I saw, how to do it came out and then sent it by form. Let me search....
0
check in <input type = "image" alt = "blablabla" />
https://www.mclibre.org/consultar/htmlcss/html/html-formularios.html
0
... Canvas does not have event support, but it can over a parent element: <div onclick = "fun (events);"> <canvas> </canvas> </div>