Area of a rectangle [SPOILER]

Question

Hey everyone,

so I just finished this exercise and wanted to test the code in the playground.
Here's the code:

length = int(input())
width = int(input())
def area(length, width):
#your code goes here
print(length * width)
if length == width:
print('Square')

area(length, width)

What blows my mind is the fact that on the exercise there's no problems but in the playground I get this error:

File "file0.py", line 6
if length == width:
^
IndentationError: unindent does not match any outer indentation level.

Any lead about it?

Thanks!

Answer 1

Learn code indentation, what it is, how it is done correctly.

https://code.sololearn.com/cT5BRIbkia21/?ref=app

Answer 2

Thanks for the link Ipang! It's very interesting and gonna keep it. I compared my code with the examples and didn't seen any problem. So what I did, was erasing all spaces and tabs and tabbed everything (not the def line) and tabbed 2 times the 'print('Square')' and it worked. Can't tell why but worked. :)
Thanks again for the help! :)

Answer 3

My pleasure,
When such thing happens, but indents doesn't seem to be having problem visually, then we look for indents inconsistency. That is, where a code was indented with different character, spaces & tabs mixed together. We should just be more consistent with the character ussd for indenting code.

This unfortunately, only affects Python because indents are means of code structuring.

Answer 4

IMaybe you should make fhe indent on your if statement a little more pronounced. It is so small it does not really look like an indent. Does that fix it?

Answer 5

length =int(input())
width=int(input())
def area(x,y):
print(x*y)
if x==y:
print("Square")
area(length,width)