Can anyone explain this??

Question

l = []
for i in range(17):
l.append(i*2)
m = [x&1 for x in l]
print(sum(m))

Answer 1

range(17) gives 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. Each value multiple itself(0,1,4,9,16,25,36,49,64,81,100,121,144,169,196,225,256). And add to list l.
Each value of list l do Bitwise AND(&) operation.
It gives 1 if both value is 1 otherwise 0.
Convert each values into binary then compare with 1
Example:
25 -> 00011001
1 -> 00000001 &
----------------------
00000001 = 1

The 1 is added to list m.
All values of list l gives the following result to m after bitwise AND operation
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1]

Then sum these values, it gives 8.

https://www.sololearn.com/learn/4072/?ref=app
https://www.sololearn.com/learn/4070/?ref=app

Answer 2

Ehem.. Vadivelan, I am sorry man, i*2 not i**2.. Can you please share any link where I can learn about bit..
I mean how 21 = 0011..?? From beginning..

Answer 3

https://www.rapidtables.com/convert/number/decimal-to-binary.html

Answer 4

You mess something bro😇