out of array index?

Question

https://code.sololearn.com/cq4xACSzkEId/?ref=app
whay this happened?(whay arr[2] is anonymous Integer?)
and other question is:
is there runtime error in c++?

Answer 1

Martin Taylor thanks it was useful for me.

Answer 2

David Dolejší Can pointers access to any place of memory?

Answer 3

David Dolejší wich apps stored that Integer on this index?

Answer 4

David Dolejší i I realized that one index after array length is always zero. (test code) why?

Answer 5

Martin Taylor are you see my code? i know character array end by null.
my code:
int arr[]={2,1};
cout<<arr[2]<<endl;//Same as *(a+2). result is anonymous Integer and arr[3] is 0 or 1 depends on compiler that i check. why?

Answer 6

Martin Taylor answer another my question about c++ (see my activity)

Answer 7

Martin Taylor
it is my another question :
using c++ language?

i love c/c++ because it is very self-description(concepts describe themselves with computer architecture) and powerful. But it no longer has much use in the world, in Windows c#(Microsoft offers c#) is used on Android java, and on the web the client uses JavaScripit and etc, If I learn it, I will forget it because I have no use. What your offer? when I mention you, are you get notification?

Answer 8

ok it is beautiful. second variable use memory cell after array because that declared after it.

Answer 9

Martin Taylor change code with it
int arr[] ={1,2};
int a=3
int b=4;
cout <<arr[2]<<endl ;
cout <<arr[3]<<endl ;
//result is 4, 3
why?
are data transfer in memory?

Answer 10

these tests depend on compiler.