Scope of variable

Question

Hi

int x;
void fun()
{
int x = 2;
{
int x = 3;
cout << ::x << endl;
}
}

Above code has int x as global variable. From fun function, ::X will print value of global variable and x will print value local to scope of {} which is 3. How can I print value of X as 2 from a local scope enclosed inside {} ?

Answer 1

I don't think it's possible. The variable x from main's scope is "shadowed" as they say.