How to make a program that answers logxY

Question

it is alogarithm program and the user will give the base and number, X is the base and Y is number

Answer 1

Well logxY answers the question "by what number do you need to involute x that it would be equal to Y?" Let's say the answer is z. Therefore I built this program that works with ints:

#include <iostream>
#include <cmath>
#include <climits>

using namespace std;

int main()
{
int x = 0;
int y = 0;
int z = INT_MIN;

cin >> x >> y;
if((x == 1) || (x < 0) || (y < 0)) return 0; //since x can't be equal to 1, less than 0 and y can't be less than 0

while(true)
{
if(pow(x, z) == y) break;
z++;
}

cout << z;

return 0;
}