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Plz help (Java)
5 odpowiedzi
+ 5
GDW Lonewolf
There is L in nextLine() method.
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KODER999
It's working fine bro because she had edited code after giving solution by me.
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String h = myVar.nextLine();
System.out.println(h);
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import java.util.Scanner;
public class Forg {
public static void main(String[] args){
Scanner myVar = new Scanner (System.in);
String input =myVar.nextLine();
System.out.println(input);
}
}
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