when i try to print double a=2343.34200000 it gives me only 2343.342 ??why this is happening can anybody tell me here

Answer 1

irl maths, there's no need to write zeroes after a decimal, so the program ignores it.
or it could be that double data-type could only store 8bytes, beyond that it can't

Answer 2

But there is a demand to print 2343.34200000 so what should i do 😟

Answer 3

Davinder Kumar

Use %.8f

double t = 2343.34200000;

printf ("%.8f\n", t);

https://code.sololearn.com/c7Vzgaqi0PNM/?ref=app

Answer 4

Use I/O manipulator from <iomanip> header

#include <iostream>
#include <iomanip> // std::fixed, std::setprecision

int main()
{
double dbl_var {2343.34200000};

std::cout << std::fixed << std::setprecision( 8 ) << dbl_var << "\n";
// Reference:
// https://en.cppreference.com/w/cpp/io/manip/fixed
// https://en.cppreference.com/w/cpp/io/manip/setprecision
return 0;
}