(Python3) No Dice? No Problem - Help with the task

Question

I've got a problem to solve that task. I'm a little bit confused about which concepts I must use to solve the problem. I've tried to solve it in two diferent ways, which I paste below.

Task

Two friends want to play backgammon, but have lost the dice.
Create a program to replace the dice. When the program is run, it should roll the dice and output the result of each die. Use random.randint() function to generate random values in the range of 1 to 6 for each dice.

1)

import random
random.seed(int(input())) #please don't touch this lane

def dice1(random.seed)
for i in range(6)
return random.randint(1,7)

def dice2(random.seed)
for i in range (6)
return random.randint(1,7)

print(dice1)
print(dice2)

2)

import random
random.seed(int(input())) #please don't touch this lane

for i in range(6):
dice1 = random.randint(1, 7)
dice2 = random.randint(1, 7)

print(dice1)
print(dice2)

Thank you in advance!

Answer 1

I might be misunderstanding the task, but i believe that this could be much simpler. A random.randint function can be used to define two dice, and then can be just printed, like so:

import random
dice1=random.randint(1,7)
dice2=random.randint(1,7)
print(dice1)
print(dice2)

Answer 2

#2 should work 👍
Put it in the code playground & run it

Answer 3

why do you use 7 for randint's second argument. a dice has six faces and if you use randint(1,7) in that case 7 included. but it should be from 1 to 6. am I wrong...