NAN and -INFINITY

Question

#include <iostream>
#include <cmath>

int main()
{
std::cout << fmax(NAN, -INFINITY);
}
// Output is "-inf"

But how?
-inf is the smallest number :)))
so everything will be larger than "-inf"

Also,
cout << fmin(INFINITY, NAN); // inf is output
But inf is the biggest number :)))))))))))

I think they should fix this in new versions of c++ ;) if there's a new version

Answer 1

fmax = Returns the larger of two floating point arguments, treating "NaNs as missing data".

(Between a NaN and a numeric value, the numeric value is chosen).

So, -inf is the only data in fmax and hence gets return.