Functions in python

Question

can anyone explain please, why the result is 9 and how does func(x)(x) an func1(x)(x) works?

def func(x):
return lambda y: (x + y + 1)

def func1(x):
return lambda y : (func(x)(x)+y+1)

print(func1(3)(1))

Answer 1

I explained here Zohrab Mammadov

https://code.sololearn.com/cSLLppSeuIos/?ref=app

Answer 2

func1(3)(1)
Here func1(3) returns a lambda, where x is 3, and y is 1. We pass 1 to the parameter of the lambda returned by func1(3).

-> lambda y: func(3)(3)+1+1

func(3)(3) works as same as func1(3)(1). Here first (3) is for the func. The second (3) is for the lambda returned by func(3).

func(3)(3) -> 3+3+1

So func(3)(3)+1+1 = 3+3+1+1+1 = 9

Answer 3

thanks a lot for your help SAYED🇧🇩🇵🇸 and CarrieForle