Is there a way to print a list when you have its name as a string?

Question

Say we have the list l= [1,2,3] and the string s= 'l'. Is there a way to get s to print l?

Answer 1

it depends on in wich scope is the variable...

if it's a global variable in the current module:

print(global()[string_variable_name])

if it's a local variable:

print(local()[string_variable_name])

if it's a variable in another module:

import other_module
print(getattr(other_module,string_variable_name))

Answer 2

another option instead of eval could be using a dictionary or a class.

dictionary example:

dict[‘I’] = [1,2,3]

class example:

class myClass():
pass

myString = myClass()
myString.I = [1,2,3]

Answer 3

l = [1,2,3]
s = 'l'
print(eval(s))

Answer 4

eval == evil

well, eval() works too, but should be avoided as could be used to do anything else (unsafe) if the string is given by untrusted user ^^

Answer 5

_dict = {"l" : [1,2,3,4]}

s = "l"

print(_dict[s])

This si the best way i just found for doing that,
It works, because you can call a dictionary Index by string.

For accesing a value from the list you just:

_dict[s][value_index]

Answer 6

In any programming language the same pedagogy applies - iterate through the list and list the items 🌻

Answer 7

No it doesn't print list of l it just print letter l

Answer 8

Yeah!!!! print(s)

Answer 9

Yah.
Answer the same, as Yr. code. sum & findings. All programming languages code work in similar format {fashion} °~° ;,.
😝😒👥👥📜